If the length of e.coli dna is 1.36 mm

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Web7 jul. 2012 · Total length of double helix DNA = total number of bp × distance between two consecutive bp. Let, the total number of bp be x. 1.36mm = x × 0.34 × 10 -9 m. x = 1.36 ×10 -3 / 0.34 × 10 -9 m. x = 4 × 10 6 bp. The number of base pairs in the given strand of DNA of E.coli are 4 X 10 6 bp WebIf the length of E. coli DNA is 1.36 mm, can you calculate the number of base pairs in E. coli ? Class:12Subject: BIOLOGYChapter: MOLECULAR BASIS OF INHERITA...

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Web4 apr. 2024 · Since we are given the length of the DNA of E.coli as 1.36 mm, we can divide this value by the distance between two consecutive base pairs to get the total number of … WebIf the length of E. coli DNA is 1.36 mm, can you calculate the number of base pairs in E.coli? In prokaryotes, such as, E. coli, though they do not have a defined nucleus, the DNA is not scattered throughout the cell. DNA (being negatively charged) is held with some proteins (that have positive charges) in a region termed as ‘nucleoid’. portosystemic shunt dog breeds

If the length of E. coli DNA is 1.36 mm, can you calculate the …

WebNo. of base pair Length between 2 bases Total length= 0.34×10−91.36×10−3= 4× 106. Web26 jan. 2024 · If the length of E. coli DNA is 1.36 mm, then how many base pairs are present in E. coil ? 8.01x - Lect 28 - Hydrostatics, Archimedes' Principle, Bernoulli's … Web15 mrt. 2024 · 6. 10 DNA FINGERPRINTING stated in the preceding section, 99.9 per cent of base sequence among prans is the same. Assuming human genome as 3 × 1 0 ∘ bp, in how ary base sequences would there be differences?It is these differences sequence of DNA which make every individual unique in their between two individuals or among … portosystemic shunt procedure

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If the length of E.coli DNA is 1.36 mm, then calculate no of base …

Web7 apr. 2024 · Since we are given the length of the DNA of E. coli as 1.36 mm, we can divide this value by the distance between two consecutive base pairs to get the total … Web6 apr. 2024 · 3-Amino-1,2,4-benzotriazine-1,4-dioxide (tirapazamine, TPZ) and other heteroaromatic N-oxides (ArN→O) exhibit tumoricidal, antibacterial, and antiprotozoal activities. Their action is attributed to the enzymatic single-electron reduction to free radicals that initiate the prooxidant processes. In order to clarify the mechanisms of aerobic … optixcam microscope camera softwareWeb4 apr. 2024 · Since we are given the length of the DNA of E.coli as 1.36 mm, we can divide this value by the distance between two consecutive base pairs to get the total number of base pairs present. Total number of base pairs= 1.36mm/0.34x 10 − 6 mm. Total number of base pairs= 4x 10 6 base pairs. Note: -In Escherichia coli, a clearly defined nucleus is ... portosystemic shunt tips

"Web24 mrt. 2024 · PDF On Mar 24, 2024, Luis Mota-Bravo and others published Detection of Horizontal Gene Transfer Mediated by Natural Conjugative Plasmids in E. coli Find, read and cite all the research you ... " - If the length of e.coli dna is 1.36 mm

If the length of e.coli dna is 1.36 mm

WebIf the length of E. coli DNA is 1.36 mm, can you calculate the number of base pairs in E. coli ? 1,441 views Feb 8, 2024 24 Dislike Share Save Doubtnut 2.1M subscribers If the … WebIf the length of E. coli DNA is 1.36 mm, then how many base pairs are present in E. coil ?Class:12Subject: BIOLOGYChapter: MOLECULAR BASIS OF INHERITANCEBook...

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WebQuestion: The genetic material of the Escherichia coli cell with a diameter of about 1 μm and a length of about 2 μm, consists of a DNA molecule with a diameter of 2 nm and a total length of 1.36 mm. (The molecule is actually circular, with a circumference of 1.36 mm.) To be accommodated in a cell that is only a few micrometers long, this large DNA molecule … WebThe length of E.coli DNA is 1,360 micron = 1.36 mm =1.36×10−3 m. And distance between two base pairs = 0.34 nm =0.34×10−9 m So, the total number of base pairs =1.36×10−3/0.34×10−9=4×106 base pairs. Suggest Corrections 3 Similar questions Q. If the length of E.coli DNA is 1,360 micron then what is the number of base pairs in this …

WebThe length of E. coli DNA and length of DNA in a human 2N cell is: (1) 1.36 mm and 2.2 m respectively (2) 1.36 mm and 2.2 mm respectively (3) 1.3 ìm and 2.2 ìm respectively (4) 1.36 cm and 2.2 cm respectively Q 329: 84 % From NCERT (1) (2) (3) (4) Subtopic: DNA Packaging Show Me in NCERT View Explanation Correct %age Add Note Bookmark Web14 nov. 2024 · july2013 Distance between two consecutive base pair = 0.34 nm Total length of given DNA = 1.36mm ∴ total no. of base pair = 1.36mm /0.34nm ⇒ 4 × 10⁶ Base pair. Advertisement abhi1o1 1.36 mm=0.36 cm lwgth of 10 base pair is 34angstrom so o.36*10^10/34=and and*9.8 or 10=ans is not it brilliant ans is there any doubt …

WebIf the length of E.coli DNA is 1.36 mm, calculate the number of base pairs it contains arrow_forward How many possible nucleotide sequences are there for a stretch of … WebHere it is given that, the length of the E.coli DNA is 1.36mm. We know the length of the DNA can be calculated by multiplying the number of base pairs into the distance …

WebIf the length of E.coli DNA is 1.36 mm, calculate the number of base pairs it contains Expert Solution Want to see the full answer? Check out a sample Q&A here See Solution …

Web8 apr. 2024 · Collateral sensitivity (CS), whereby resistance to one drug is accompanied by increased sensitivity to another, provides new opportunities for antimicrobial drug discovery. Here, Liu et al. screen ... optixpacs.com.brWebIf the length of E.coli DNA is 1.36 mm, then how many base pairs are present in E.coli ? Q. If the length of E.coli DN A is 1.36mm, then how many base pairs are present in … optixpacsWeb27 mei 2024 · If the length of E.Coli DNA is 1.36 mm, Calculate the number of base pairs it contains. molecular basis of inheritance class-12 1 Answer +1 vote answered May 27, … portosystemic varices icd 10WebTotal length of double helix DNA = total number of base pairs X distance between two consecutive bp 1.36mm = x X 0.34 X 10−9m by solving this we get, x = 4 X 106bp So the … optixcare lysine chewsWebSolution: In the given case, the number of base pairs for E. coli would be 4×106 bp. It can be calculated as. Average distance between two base pairs of DNA is 3.4A˚. Length of E. coli DNA is = 1.36× 107A˚. So, number of nucleotides = 3.4A˚1.36×107A˚ = 0.39 ×107. optixsoft traceviewerWebIf the length of E. coli DNA is 1.36 mm, can you calculate the number of base pairs in E.coli? Yes In prokaryotes, such as, E. coli, though they do Solution Verified by Toppr … optixstar k662c ethernet terminalWeb26 aug. 2024 · If the length of E.Coli DNA is 1.36 mm, Calculate the number of base pairs it contains. asked May 27, 2024 in Biology by Farhat (78.2k points) molecular basis of inheritance; class-12; 0 votes. 1 answer. Calculate the length of the DNA of bacteriophage lambda that has 48502 base pairs. optixfab