WebNov 18, 2024 · The default behaviour of the %f printf specifier is to print floating point numbers with 6 decimal places. To limit the decimal places to 1, we can specify a precision in the following manner: $ printf "%.1f\n" 255 0xff 0377 3.5 255.0 255.0 377.0 3.5 Formatting to three places with preceding zeros: WebAug 24, 2012 · #!/bin/bash echo "Insert the price you want to calculate:" read float echo "This is the price without taxes:" echo "scale=2; $float/1.18" bc -l read -p "Press any key to continue..." bash scriptname.sh Assuming that the price is: 48.86 The answer will be:41.406779661 (41.40 actually because I'm using scale=2;)
Floating Division in Linux - UNIX
WebSep 16, 2016 · 1. The subexpression 1/5 does not create a non-integer value. It creates the integer value 0, since the result of integer division of 1 by 5 is 0. Further operations successfully use that value of 0. This isn't what the OP intended, but no operation creates a non-integer value and no operation fails. – Eliah Kagan. WebAug 27, 2024 · How to do integer & float calculations, in bash or other languages/frameworks? (17 answers) Simple command-line calculator (21 answers) Closed 3 years ago. Hi I have to divide two numbers in #!/bin/sh $x = 5678 $x/1000 but calculations return only integer: 5. I need 5,678. I've tried $x/1000.0 $x/1000.0 bc on first method … dyson ball origin upright bagless vacuum
How do I use floating-point arithmetic in bash? - Stack Overflow
WebDivision; because all numbers in awk are floating-point numbers, the result is not rounded to an integer—‘ 3 / 4 ’ has the value 0.75. (It is a common mistake, especially for C programmers, to forget that all numbers in awk are floating point, and that division of integer-looking constants produces a real number, not an integer.) x % y Web2 days ago · I don't know enough about how IEEE floating-point values work to know for sure what bits to put where in order to get the values I'm going for. I think (and am wrong) that I can just right-shift a ulong by 12 bits (thus turning the top 52 bits into the bottom 52 bits), add 2^52 (setting the bottom bit of the exponent to 1), and then ... WebFeb 19, 2016 · Basically in Bash, what I'm trying to do is take a input of seconds from a user and find the hours. So basically if the user enter 35 the output should be 0.00972222. But bash gives me is a zero. heres the command I have: echo "Enter the seconds you wish to convert to hours: " && read sec && echo " $ ( (sec/3600)) is the amount of hours " dyson ball reverse air blowing out